It's called the Redskins Rule, and it has an accuracy rate of either 94 or
100 percent depending on how it's applied. Every time the Redskins win their
final home game before a presidential election, the candidate representing the
incumbent party remains in office. Every time they lose, the incumbent party's
candidate loses as well. It's a predictor that has worked in 16 of 17
presidential elections since the Redskins arrived in Washington. (Some argue the
rule is 17-for-17; more on that in a second.)In 2004, the Redskins lost to the Packers 28-14, suggesting Bush should
have lost to John Kerry. Hirdt changed the way the rule is applied to have it
refer to the previous winner of the popular vote, not the electoral vote.That's good news for Barack Obama and the Democrats.
Schadenfreude 359 (A Continuing Series)
1 month ago
3 comments:
With this coincidence being based on the Redskins winning, it's a wonder that incumbents ever get re-elected
I think the use of the word "crown" instead of "inaugurate" is appropriate here (in fact, I'm surprised he didn't say "crown of thorns")
I think this guy got it wrong though, mostly because Kerry didn't win the popular vote in 2004. According to sportscenter, it was changed after '04 to "in a year when the incumbent isn't on the ballot, the incumbent party will win or lose according ot what happens to the 'skins"
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